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30x^2-14x-8=0
a = 30; b = -14; c = -8;
Δ = b2-4ac
Δ = -142-4·30·(-8)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-34}{2*30}=\frac{-20}{60} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+34}{2*30}=\frac{48}{60} =4/5 $
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